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29 January, 07:55

Suppose that we have a fuse box containing 20 fuses, of which 5 are defective. If 2 fuses are selected at random and removed from the box in succession without replacing the first, what is the probability that both fuses are defective?

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Answers (2)
  1. 29 January, 09:28
    0
    0.0526 (3 sf)

    Step-by-step explanation:

    (5/20) * (4/19)

    = 0.0526315789

    = 0.0526 (3 sf)
  2. 29 January, 10:40
    0
    Unlikely

    Step-by-step explanation:

    Because that leaves 15 lives fuses
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