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17 February, 23:34

What is the solution set of 2x2-3x=5

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  1. 18 February, 02:44
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    You use the quadratic formula:

    2x {}^{2} - 3x = 5

    2x {}^{2} - 3x - 5 = 0

    x = / frac{3 + - / sqrt{9 - 4 (2) ( - 5) }}{2 / times 2}

    x = / frac{3 + - / sqrt{49} }{4}

    x = / frac{3 + 7}{4} / : and / : x = / frac{3 - 7}{4}

    x = / frac{5}{2} / : and / : x = - 1
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