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15 October, 18:59

A ball is thrown from ground level straight up into the air at an intitial velocity of 54 feet per second. The height of the ball t seconds after it is thrown is given by the formula h (t) = 54t-16'2. How many seconds after the ball is thrown will it return to the ground

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  1. 15 October, 19:45
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    3 3/8 seconds.

    Step-by-step explanation:

    When it reaches the ground h = 0 so:

    54t - 16t^2 = 0

    16t^2 - 54t = 0

    2t (8t - 27) = 0

    t = 0 or t = 27/8 (we ignore the t = 0) so:

    t = 3 3/8 seconds.
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