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15 October, 18:53

What is the solution to the following system? x+y+z=6 x-y+z=8 x-y-z=0

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  1. 15 October, 22:04
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    (6,-1,1)

    Step-by-step explanation:

    First pair two of the equations together twice:

    I chose x+y+z=6 and x-y+z=8

    Used the elimination method and eliminated the y's and got x+z=7

    Then I took another pair of equations x+y+z=6 and x-y-z=0

    Using the elimination method I once again eliminated the y's (and z's) and got x=6

    I then plugged x=6 into x+z=7 and got that z=1

    I then plugged x=6 and z=1 into the original equation x+y+z and got y=-1

    Thus, x=6 7=-1 z=1 and in coordinate form (6,-1,1).
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