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15 December, 11:30

Given the equation (x+2) (x+3) (x+5) = (x+2) (x-3) (x+5), what can we conclude about the solutions

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  1. 15 December, 15:05
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    Hello,

    (x+2) (x+3) (x+5) = (x+2) (x-3) (x+5)

    ==> (x+2) (x+5) (x+3 - (x-3)) = 0

    ==> (x+2) (x+5) * 6=0

    ==>x=-2 or x=-5
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