Find the equation in standard form. of the line that passes through (-2,4) and (1,-2)

To find the equation in standard form of the line. First solve for the m value - slope.

(-2,4) and (1,-2)

M = y2 - y1 / x2 - X1

M = - 2 - 4 / 1 - - 2

M = - 6/3

M = - 2.

Y - y1 = m (X - x1)

Y - 4 = - 2 (X + 2)

Y - 4 = - 2 (X + 2)

Y - 4 = - 2x - 4

Y - 4 + 4 = - 2x - 4 + 4

Y = - 2x.

Y - Y = - 2x - Y

0 = - 2x - Y

-2x - Y = 0.

I believe the standard form equation of the line is - 2x - Y = 0.

-3 will be your slope and your y-intercept will be - 2 ... equation i: y=-3x-2