How would you find the zeros of the function by rewriting the function in intercept form? Ex: y=x^2-12x+32

Question

Mathematics

Rory Mcneil

30 March, 01:09

How would you find the zeros of the function by rewriting the function in intercept form? Ex: y=x^2-12x+32

+2

Answers (2)

Know the Answer?

Clayton Huffman · Answer 1

The way i do it is factor x^2-12x+32 into (x-8) (x-4) then set each of those to zero which would look like 0=x-8 and 0=x-4. Then solve each equation and your answers would be x=8 and x=4

Brylee Santana · Answer 2

x² - 12x + 32 = 0

Δ = (-12) ² - 4 * 1 * 32 = 144 - 128 = 16

√Δ = 4

x₁ = (12-4) / 2 = 4

x₂ = (12+4) / 2 = 8