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20 January, 16:06

Express answer in exact form.

Find the area of the larger segment whose chord is 8" long in a circle with an 8" radius.

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  1. 20 January, 16:23
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    A chord and a radius form an equilateral triangle.

    The area of the larger segment is:

    A = 5/6 r² π + r²√3/2 = 5/6 · 64 · 3.14 + 32 · 1.73 =

    = 167.47 + 55.36 = 222.83 in²
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