Assume the function has an inverse. Without solving for the inverse find the indicated function values: f (x) = x^3+4x-1, (a) f^-1 (-1) (b) f^-1 (4) ... ?

F (x) = x³ + 4x - 1

The domain of a function is the range of its inverse and the range of a function is the domain of its inverse. Thus, to find f⁻¹ (x), we put the given value of x into f (x) of the original equation.

a) - 1 = x³ + 4x - 1

x = 0

f⁻¹ (-1) = 0

b) 4 = x³ + 4x - 1

x = 0.25

f⁻¹ (4) = 0.25