What 3 consecutive numbers add up to 237?

Take the three consecutive numbers as x, x+1 and x+2. These three have to add up to 237 so we get the equation:

x + (x+1) + (x+2) = 237

3x + 3 = 237

3x = 234

x = 234 / 3 = 78

Therefore the numbers are x (78), x+1 (79) and x+2 (80)

Let three consecutive numbers be a-1, a, a+1

sum of above (a-1) + (a) + (a+1) = 237

3a = 237

a = 79

therefore three numbers are = 78, 79,80