Lo bisects nlm lm=18 no=4 and ln=10. what is the value of x

I found the figure that accompanies this problem.

ΔLMN; LO bisects the triangle creating 2 right triangles.

Δ LOM and Δ LON

Δ LOM; hypotenuse = LM = 18; short leg = OM = x

Δ LON; hypotenuse = LN = 10; short leg = NO = 4

similar triangles but not congruent.

hypotenuse / short leg:

18/x = 10/4

cross multiplication:

18 * 4 = 10 * x

72 = 10x

72/10 = x

7.2 = x

18/x = 10/4

18/7.2 = 10/4

2.5 = 2.5