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Mathematics
Waylon Williamson
4 August, 12:14
Solve:
sin (2x) = sqrt (3) / 2
I
+4
Answers (
1
)
Devan Weiss
4 August, 15:07
0
In order to solve this you will need to use inverse sin function like this:
sin^-1 ((-sqrt3) / 2) = 2x
sin^-1 ((-sqrt3/2) = 5pi/3
5pi/3 = 2x
(5pi/3) / 2
5pi/6
is the answer.
I hope this goes good
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