Identify the factors of x2-8x-20

Simplifying x2 + - 8x = 20 Reorder the terms: - 8x + x2 = 20 Solving - 8x + x2 = 20 Solving for variable 'x'. Reorder the terms: - 20 + - 8x + x2 = 20 + - 20 Combine like terms: 20 + - 20 = 0 - 20 + - 8x + x2 = 0 Factor a trinomial. (-2 + - 1x) (10 + - 1x) = 0 Subproblem 1Set the factor ' (-2 + - 1x) ' equal to zero and attempt to solve: Simplifying - 2 + - 1x = 0 Solving - 2 + - 1x = 0 Move all terms containing x to the left, all other terms to the right. Add '2' to each side of the equation. - 2 + 2 + - 1x = 0 + 2 Combine like terms: - 2 + 2 = 0 0 + - 1x = 0 + 2 - 1x = 0 + 2 Combine like terms: 0 + 2 = 2 - 1x = 2 Divide each side by '-1'. x = - 2 Simplifying x = - 2 Subproblem 2Set the factor ' (10 + - 1x) ' equal to zero and attempt to solve: Simplifying 10 + - 1x = 0 Solving 10 + - 1x = 0 Move all terms containing x to the left, all other terms to the right. Add '-10' to each side of the equation. 10 + - 10 + - 1x = 0 + - 10 Combine like terms: 10 + - 10 = 0 0 + - 1x = 0 + - 10 - 1x = 0 + - 10 Combine like terms: 0 + - 10 = - 10 - 1x = - 10 Divide each side by '-1'. x = 10 Simplifying x = 10Solutionx = {-2, 10}

I factored and got:

(x - 10) (x + 2)

so I set each to 0 ... and got 10 and - 2