Find the real zeros of the trigonometric function on the interval 0 ≤ x < 2π

f (x) = 4 cos^2 (x) - 3

Question

Mathematics

Walter Ware

23 April, 21:35

Find the real zeros of the trigonometric function on the interval 0 ≤ x < 2π

f (x) = 4 cos^2 (x) - 3

+2

Answers (2)

Know the Answer?

Moonshine · Answer 1

F (x) = 4 [cos (x) ]^2 - 3 = 0

4[cos (x) ]^2 = 3

cos (x) = √3 / 2

That happens in the first and fourth quadrants, for the angles 30 degrees and 330 degrees.

Answer: x = 30 degrees and x = 330 degrees

Scott Klein · Answer 2

4cos2 (x) - 3=0

or

4cos2 (x) = 3

cos (x) = √3/2

π/6, 5π/6, 7π/6, 11π/6

Find the real zeros of the trigonometric function on the interval 0 ≤ x < 2πf (x) = 4 cos^2 (x) - 3

Find the real zeros of the trigonometric function on the interval 0 ≤ x < 2π

f (x) = 4 cos^2 (x) - 3