An object is launched from a platform. Its height (in meters), x seconds after the launch, is modeled by h (x) = - 5 (x+1) (x-9)

What is the height of the object at the time of launch?

Because the time right at launch equals 0 (0 seconds have passed since the launch) solve the equation for 0.

-5 (0 + 1) (0 - 9)

-5 (1) (-9)

-5 (-9)

45

The object was 45 metres above the ground at the time of the launch.

-5 (1) (-9) = - 5 (-9) = when the numbers are both negative it becomes positive so you multiply your numbers and the answer is 45