If a=4b^2 and b=-1/2e^2, what is the value of a to the nearest tenth?

Question

Mathematics

Elvis Henry

18 September, 06:22

If a=4b^2 and b=-1/2e^2, what is the value of a to the nearest tenth?

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Answers (1)

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Jaylon Stokes · Answer 1

To answer, it is assumed that e here is the Euler number which is equal to 2.718. Substitute this value to the e of the second equation to get the value of b.

b = 0.5 (2.718^2) = 3.6945

Then, we substitute this value to the first equation to get the value of a.

a = 4 (3.6945^2) = 54.498

Thus, the answer is approximately equal to 54.5.