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24 March, 17:18

How do you verify the trigonometry expression cscx-1=1-sinx/sinx

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  1. 24 March, 18:14
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    Cscx = 1/sinx

    So substitute cscx for 1/sinx

    1/sinx - 1

    1 can be written in terms of sinx

    1 = sinx/sinx (anything over itself is 1)

    1/sinx - sinx/sinx = (1 - sinx) / sinx
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