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1 March, 14:36

How do you factorize p2 + 2p - 3 = 0

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Answers (1)
  1. 1 March, 15:05
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    Solution

    p = {-3, 1}

    Step-by-step explanation:

    Simplifying

    p2 + 2p + - 3 = 0

    Reorder the terms:

    -3 + 2p + p2 = 0

    Solving

    -3 + 2p + p2 = 0

    Solving for variable 'p'.

    Factor a trinomial.

    (-3 + - 1p) (1 + - 1p) = 0

    Subproblem 1

    Set the factor ' (-3 + - 1p) ' equal to zero and attempt to solve:

    Simplifying

    -3 + - 1p = 0

    Solving

    -3 + - 1p = 0

    Move all terms containing p to the left, all other terms to the right.

    Add '3' to each side of the equation.

    -3 + 3 + - 1p = 0 + 3

    Combine like terms: - 3 + 3 = 0

    0 + - 1p = 0 + 3

    -1p = 0 + 3

    Combine like terms: 0 + 3 = 3

    -1p = 3

    Divide each side by '-1'.

    p = - 3

    Simplifying

    p = - 3

    Subproblem 2

    Set the factor ' (1 + - 1p) ' equal to zero and attempt to solve:

    Simplifying

    1 + - 1p = 0

    Solving

    1 + - 1p = 0

    Move all terms containing p to the left, all other terms to the right.

    Add '-1' to each side of the equation.

    1 + - 1 + - 1p = 0 + - 1

    Combine like terms: 1 + - 1 = 0

    0 + - 1p = 0 + - 1

    -1p = 0 + - 1

    Combine like terms: 0 + - 1 = - 1

    -1p = - 1

    Divide each side by '-1'.

    p = 1

    Simplifying

    p = 1

    Solution

    p = {-3, 1}
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