How do you factorize p2 + 2p - 3 = 0

Solution

p = {-3, 1}

Step-by-step explanation:

Simplifying

p2 + 2p + - 3 = 0

Reorder the terms:

-3 + 2p + p2 = 0

Solving

-3 + 2p + p2 = 0

Solving for variable 'p'.

Factor a trinomial.

(-3 + - 1p) (1 + - 1p) = 0

Subproblem 1

Set the factor ' (-3 + - 1p) ' equal to zero and attempt to solve:

Simplifying

-3 + - 1p = 0

Solving

-3 + - 1p = 0

Move all terms containing p to the left, all other terms to the right.

Add '3' to each side of the equation.

-3 + 3 + - 1p = 0 + 3

Combine like terms: - 3 + 3 = 0

0 + - 1p = 0 + 3

-1p = 0 + 3

Combine like terms: 0 + 3 = 3

-1p = 3

Divide each side by '-1'.

p = - 3

Simplifying

p = - 3

Subproblem 2

Set the factor ' (1 + - 1p) ' equal to zero and attempt to solve:

Simplifying

1 + - 1p = 0

Solving

1 + - 1p = 0

Move all terms containing p to the left, all other terms to the right.

Add '-1' to each side of the equation.

1 + - 1 + - 1p = 0 + - 1

Combine like terms: 1 + - 1 = 0

0 + - 1p = 0 + - 1

-1p = 0 + - 1

Combine like terms: 0 + - 1 = - 1

-1p = - 1

Divide each side by '-1'.

p = 1

Simplifying

p = 1

Solution

p = {-3, 1}