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12 August, 20:43

E bisects line segment df. df=2y, and ef=8y-3. find de, ef, and df.

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  1. 12 August, 21:05
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    1/2DF = EF

    1/2 (2y) = 8y - 3

    Multiply 1/2 * 2y.

    y = 8y - 3

    Subtract 8y from both sides.

    -7y = - 3

    Divide both sides by - 7.

    y = 3/7

    Plug 3/7 for y into DF and EF.

    DF: 2 (3/7) = 6/7

    EF: 8 (3/7) - 3 = 24/7 - 3 = 3/7

    EF = DE because they are bisected, so DE = 3/7
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