Is k-2 a factor of (k^3-k^2-k-1) / (k-2)

Hello from MrBillDoesMath!

Answer:

k-2 is not a factor of k^3-k^2-k-1.

Discussion:

I think you are asking if k-2 is a factor of (k^3-k^2-k-1). If it were, then substituting k = 2 in the polynomial would yield 0. Let's check:

2^3 - 2^2 - 2 - 1 = "k^3-k^2-k-1"

8 - 4 - 2 - 1 = 1 0.

So k-2 is not a factor of k^3-k^2-k-1.

Regards,

MrB

P. S. I'll be on vacation from Friday, Dec 22 to Jan 2, 2019. Have a Great New Year!