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25 May, 00:48

How many partitions of $12$ are there that have at least four parts, such that the largest, second-largest, third-largest, and fourth-largest parts are respectively greater than or equal to $4,3,2,1$?

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  1. 25 May, 04:30
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    4, 4, 2, 2

    4, 3, 3, 2

    Step-by-step explanation:

    Given data in the problem:

    total value = 12

    now,

    each partition should be greater than or equal to 4, 3, 2, 1

    now, the sum of the above terms comes as:

    4 + 3 + 2 + 1 = 10

    difference from the original values : 12 - 10 = 2

    so we can divide 2 into two equal parts to the number 3 and 1

    thus, we get the partitions as:

    4, (3 + 1), 2, (1 + 1) = 4, 4, 2, 2

    and another partition can be

    4, 3, (2 + 1), (1 + 1) = 4, 3, 3, 2
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