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26 August, 20:16

The second of three numbers is 6 more than the first. The third number is twice the first. The sum of the three number is 26. Find the three numbers

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  1. 26 August, 21:12
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    Let's have the first number be x, the second number y, and the third number z.

    Because the second number is six more than the first, y = x + 6.

    Because the third number is twice the first, z = 2x.

    The three numbers added together equals 26, so 26 = x + y + z.

    Let's substitute y = x + 6 and z = 2x into 26 = x + y + z. This gives us:

    26 = x + x + 6 + 2x

    26 = 4x + 6

    We subtract 6 from both sides of the equation and divide by 4 to get:

    5 = x

    Now, we'll put x = 5 into our previous to equations to find y and z:

    y = 5 + 6

    y = 11

    z = 2*5

    z = 10

    Let's check out answer. 10 + 11 + 5 = 26. 10 is twice of 5 and 11 is 6 more than 5. Thus our three numbers are 10, 11, and 5.
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