A baseball team has three positions open: first base,

third base, and right field. Six players are trying out

for these positions. In how many different ways can

these positions be filled?

Question

Mathematics

Nikolas Bray

31 March, 19:20

A baseball team has three positions open: first base,

third base, and right field. Six players are trying out

for these positions. In how many different ways can

these positions be filled?

+5

Answers (1)

Know the Answer?

Ellie Griffith · Answer 1

Number of different ways of placing the players are 120

Explanation:

Given:

Three positions in baseball team are there = __ __ __

Number of players trying = 6

Number of ways in which these positions can be filled = ?

6 __ __ in first position, all 6 players have the chances to be positioned

6 5 __ In second position, 5 players have the chances to be positioned

6 5 4 In third position, 4 players have the chances to be positioned.

Therefore, different ways in which the players can be positioned = 6 X 5 X 4

= 120

A baseball team has three positions open: first base,third base, and right field. Six players are trying outfor these positions. In how many different ways canthese positions be filled?

A baseball team has three positions open: first base,

third base, and right field. Six players are trying out

for these positions. In how many different ways can

these positions be filled?