A bag contains 6 blue marbles 10 red marbles and 9 green marbles. If 2 marbles are drawn at random without replacement what is the probability that to green marbles are drawn

P (1 and 2 are green) = 3/25

Step-by-step explanation:

We need to know the total number of marbles

6 Blue + 10 red + 9 green = 25 marbles

P (1st marble is green) = green / total

= 9/25

Since we don't put it back, there are

6 Blue + 10 red + 8 green = 24 marbles

P (2st marble is green) = green / total

= 8/24 = 1/3

P (1 and 2 are green) = P (1st green) * P (2nd green)

= 9/25 * 1/3

= 3/25