What is the sum of the √-2 and √-18?

The sum is 4 i√2

Step-by-step explanation:

Both the numbers √-2 and √-18 are imaginary number and thus can be presented as

i√2 and i√18

On simplifying, the i√18 can be written as i√ (9 x 2)

Taking out square root of 9 we get-

3i√2

Thus the summation of i√2 and i√18 can be written as

i√2 + 3i√2

= 4 i√2

The correct answer is (4 √2) i

Step-by-step explanation:

The sum we are looking is "x"

x = √-2 + √-18

By the Radical Properties of Multiplication,

x=√-2 + √ (-2*9)

x=√-2 + √-2 * √9

Considering √-2 = √ ((-1) * 2) = √-1 * √2

According to the propriety of complex numbers, we can say

i=√-1

Replacing

x = i √2 + 3 i√2

The answer is x = (4 √2) i