a rectangle has an area of 2020cm square all side lengths are a whole number of centimetres what is the greatest possible number of centermetres in the perimeter of the rectangle

(Assuming the correct area is 20 cm2)

Perimeter = 42 cm

(Assuming the area really is 2020 cm2)

Perimeter = 4042 cm

Step-by-step explanation:

(Assuming the correct area is 20 cm2)

If we call the length L and the width W, we have:

L * W = 20

Perimeter = 2L + 2W

The minimum perimeter occurs when the sides have values near to each other. In this case, it would be length = 4 and width = 5, with a perimeter of 18 cm

To maximize the perimeter, we need to set one of the sides to 1 cm, so the other side will have a higher value, and so the perimeter.

If a width of 1, we have:

L * 1 = 20

L = 20 cm

Perimeter = 2*20 + 2*1 = 42 cm

(Assuming the area really is 2020 cm2)

If the width = 1 cm, we have:

L * 1 = 2020

L = 2020 cm

Perimeter = 2*2020 + 2*1 = 4042 cm