Completely factor 4x^3 - 12x^2 + 2x - 6

A. (4x^2 + 3) (x - 2)

B. (4x^2 + 2) (x - 3)

C. (4x^2 - 2) (x + 3)

D. (4x^2 - 3) (x + 2)

B. (4x^2 + 2) (x - 3)

Step-by-step explanation:

4x^3 - 12x^2 + 2x - 6

Factor by grouping

4x^3 - 12x^2 + 2x - 6

Factor 4x^2 out of the first group and 2 out of the second group

4x^2 (x-3) + 2 (x-3)

Now factor out (x-3)

(x-3) (4x^2 + 2)

To factor completely we should factor out a 2

(x-3) 2 (2x^2 + 1)

2 (x-3) (2x^2+1) but since this is not one of the choices, go with B