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14 January, 06:08

if there is a 10% chance of sun tomorrow and 20% chance of wind and no sun what is the probability that it is windy given that it is not sunny? round your answer to the nearest percent

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  1. 14 January, 07:05
    0
    =22%

    Step-by-step explanation:

    Since we have given two conditions simultaneously that is windy and not sunny. So we will use the concept of conditional probability.

    The probability of sunny day = P (sunny) = 10%

    P (sunny) = 10%=0.1

    The probability of windy and not sunny=P (windy|not sun) = 20%

    P (windy|not sun) = 20% = 0.2

    Now divide the both probabilities:

    P (windy|not sun) / P (sunny)

    =0.2/[1-0.1]

    {Hence there are 10% chances of sun tomorrow than there are (1 - 0.1) chances of no sun}

    If we subtract 1 from 0.1 than it becomes:

    =0.2/0.9

    =2/9

    =0.2222222222

    =22%

    Hence the probability that it is windy = 22% ...
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