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24 October, 04:59

How many solutions are there to the following system equations?

Use the linear combination method.

2d+e=8

d-e=4

A. The solution is (4,0)

B. There is no solution

C. There are an infinite number of solutions

D. The solution is (5,-2)

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Answers (1)
  1. 24 October, 06:12
    0
    Indinite

    2d+e=8 d-e=4

    common multiple=16, 32, 64

    16-12=4 16-4=12
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