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21 August, 21:05

Using an equation or inequality to solve the problem associated with the scenario:

A rectangle has a length at least four more than five times the width. If the perimeter is at least 44 units, find the least possible width.

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  1. 21 August, 23:17
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    Where w=width, l=length

    perimeter = 2w + 2l

    44 ≥ 2w + 2 (5w+4)

    44 ≥ 2w + 10w+8

    44 ≥ 12w + 8

    44 (-8) ≥ 12w + 8 (-8)

    36 ≥ 12w

    36 (:12) ≥ 12w (:12w)

    3 ≥ w

    least possible width is 3
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