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15 February, 13:24

Tim has two spinners, spinnerA and spinner B. Each spinner can only land on red or blue. The probability that spinner A will land on red is 0.5. The probability that spinnerB will land on red is 0.6. Tim spins spinner A once and he spins spinnerB once. He does this a number of times. The number of times both spinners land on red is 84. Workout an estimate for the no of time both spinners land on blue.

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  1. 15 February, 14:48
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    An estimate for the number of times that both spinners land on blue is 69 times.

    Step-by-step explanation:

    Let's call x the number of times that Tim spins spinner A. x is also equal to the number of times that Tim spins spinner B because the question said that Tim spins spinner A once and he spins spinner B once.

    Now, we can formulate the following equation:

    0.5*x + 0.6*x = 84

    Because 50% of the times that Tim spins spinner A, that spinner will land on red and 60% of the times that Tim spins spinner B, that spinner will land on red.

    So, solving the equation for x, we get:

    0.5*x + 0.6*x = 84

    1.1*x = 84

    x = 84/1.1 = 76.3636

    Now, an estimate for the number of times that both spinners land on blue can be calculated as:

    0.5*x + 0.4*x

    Because 50% of the times that Tim spins spinner A, that spinner will land on blue and 40% of the times that Tim spins spinner B, that spinner will land on blue.

    Finally, replacing x by 76.3636, we get

    0.5 (76.3636) + 0.4 (76.3636) = 68.7272

    it means that an estimate for the number of times that both spinners land on blue is 69 times.
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