The number of clients arriving at a bank machine is Poisson distributed with an average of 2 per minute. What is the probability that no more than 2 customers will arrive in a minute

The probability that no more than '2' customers will arrive in minute = 1.5412

Step-by-step explanation:

Explanation:-

Mean of the Poisson distribution 'λ' = 2 per minute

P (X=x) = e⁻ˣ λˣ/x!

The probability that no more than '2' customers will arrive in minute

P (x≤ 2) = P (x=0) + P (x=1) + P (x=2)

= e⁻² (2) °/0! + e⁻² (2) ¹/1!+e⁻² (2) ²/2!

= 1 + 0.2706 + 0.2706

= 1.5412

The probability that no more than '2' customers will arrive in minute = 1.5412