How do you solve, 2=2y-x and 23=5y - 4x, using the substitution method

2 = 2y - x

23 = 5y - 4x

isolate the x in the first equation

x = 2y - 2

now use this to substitute x in the second equation

23 = 5y - 4 (2y - 2)

23 = 5y - 8y + 6

23 = - 3y + 6

-3y = 17

y = - 5 2/3 (5.6 repeating)

now use that to find x in either equation.

2 = 2 (-5.66666) - x

2 = - 11.3 repeating - x

13.3 repeating = - x

x = - 13.3 repeating

optional * * use the second equation to check