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14 April, 09:55

A man measured his height and found 5.7 feet. However, after he carefully measured his height a second time, he found his real height to be 5 feet. What is the percent error the man made the first time he measured his height?

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Answers (2)
  1. 14 April, 12:15
    0
    14%

    Step-by-step explanation:

    percent error = (experimental measure - real measure) / (real measure) * 100%

    percent error = (5.7 ft - 5 ft) / (5 ft) * 100%

    percent error = (0.7 ft) / (5 ft) * 100%

    percent error = 0.14 * 100%

    percent error = 14%
  2. 14 April, 12:32
    0
    percentage error = 12.28%

    Step-by-step explanation:

    5 x 0.14 = 0.7

    5 x 1.14 = 5.7

    as increase is not the same as error decrease.

    We use the same numbers 12.28% = 0.1228.

    5.7 x 0.1228 = 0.69996 = 12.28%

    5.7 - 0.69996 = 5.00004 foot. As decrease.

    And find it is correct.

    His error therefore was 12.28% out.

    As we work the first numbers 5.7 and can only x by a number to see 5ft

    We take 5.7 x 0.1228 and find 0.69996 when taken from 5.7 ft. is unmistakably 5 foot. (5.00004) ft.
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