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24 August, 06:59

If (a-2) ^2 + (b+1) ^2 + (c-3) 2 = 0 then the value of a^2/4+b^2+c^2/3

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Answers (2)
  1. 24 August, 09:37
    0
    5

    Step-by-step explanation:

    (a-2) ^2 + (b+1) ^2 + (c-3) ^2 = 0

    Since all 3 terms are square numbers, they must be = 0 to have a sum of 0.

    so a-2 = 0, b+1=0 and c-3 = 0

    a=2, b = - 1, c = 3

    a^2/4+b^2+c^2/3 = 4/4+1+9/3 = 1+1+3 = 5
  2. 24 August, 10:51
    0
    The correct answer is 2. a = 1/2, b = - 3, c = - 2

    Step-by-step explanation:

    1. Let's review the information provided for an answering the question correctly:

    0 = 1/2x^2 - 3x - 2

    0 = 1/2x² - 3x - 2

    2. Let's find the values for a, b and c.

    According to the quadratic equation, we have:

    a = 1/2

    b = - 3

    c = - 2

    The correct answer is 2. a = 1/2, b = - 3, c = - 2

    (❤'艸`❤)
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