 Mathematics
5 June, 10:33

# How to determine whether the given function is even, odd, or neither?f (x) = x^3 + x^2 + 3

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Answers (1)
1. 5 June, 11:31
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f (x) = x^3 + x^2 + 3x^0 is neither even nor odd. Why? Because we have a mixture of even and odd powers of x here: x^3 (odd) and x^2 and x^0 (even).

Even functions: all component functions are even (e. g., x^2 and x^0).

Odd functions: all component functions are odd (e. g., x^5 and x^3.

Neither: There's a mixture of even ad odd functions.

Another way to test for even, odd or neither:

Even functions: f (-x) = f (x). Changing the sign of the input (x) doesn't change the sign of the output.

Odd functions: f (-x) = - f (x). Changing the sign of the input changes the sign of the output.
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