How many solutions are there to the equation x2 + 7x - 6 = 0?

two real roots

Step-by-step explanation:

x^2 + 7x - 6 = 0

We can use the discriminant

This is in the form ax^2 + bx+c=0

b^2 - 4ac

If b^2 - 4ac> 0 there are 2 real roots

If b^2 - 4ac = 0 there is one real root

If b^2 - 4ac <0 there are two complex roots

7^2 - 4 (1) * (-6)

49 + 24

73

Since 73 > 0 there are two real roots