If the top of a rectangular table has an area of 35in^2, and its dimensions have a sum of 12, what are the dimensions?

Length is 8 m and width is 4 m.

Step-by-step explanation:

Given,

The area of the rectangular table = 35 sq m

Sum of its dimensions = 12 m

To find the length and width of the table.

Let, the length and width of the table is l and b respectively.

As per the problem,

lb = 35 and l+b = 12

Formula

(a-b) ² = (a+b) ²-4ab

Now,

(l-b) ² = (l+b) ²-4lb

= (12) ²-4*35 = 4

so, (l-b) = 2

Now we will solve l+b = 12 and l-b = 4

By adding we get,

l+b+l-b = 12+4

or, 2l = 16

or, l = 8

And b = 12-l = 12-8 = 4

Hence,

Length is 8 m and width is 4 m.