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11 November, 12:57

Given: △AFD, m∠F=90°

DF=7√3, m∠D=30°

Find: Area of △AFD

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Answers (1)
  1. 11 November, 15:10
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    Using the definition of the tangent function, you can find ...

    ... FA = DF·tan (30°) = (7√3) · (1/√3) = 7

    Then the usual formula for triangle area can be used:

    ... Area = (1/2) bh = (1/2) · (7√3) (7)

    ... Area = (49/2) √3 square units

    ... ≈ 42.44 square units
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