At time t, there are 216t + 18 bacteria of type A and 362t + 8 bacteria of type B organisms in a sample. When will the number of each type of bacteria be equal?

Answers voices are:

A) t=38

B) t=-38

C) t=6

D) t=9/4

Question

Mathematics

Hood

15 March, 06:52

At time t, there are 216t + 18 bacteria of type A and 362t + 8 bacteria of type B organisms in a sample. When will the number of each type of bacteria be equal?

Answers voices are:

A) t=38

B) t=-38

C) t=6

D) t=9/4

+5

Answers (1)

Know the Answer?

Jaslene Burke · Answer 1

We must set the two expressions to be equal:

216t + 18 = 362t + 8

Subtract 216t from both sides:

18 = 146t + 8

Subtract 8 from both sides:

10=146t

Divide both sides by 146:

t = 10/146 = 5/73

At time t, there are 216t + 18 bacteria of type A and 362t + 8 bacteria of type B organisms in a sample. When will the number of each type of bacteria be equal?Answers voices are:A) t=38B) t=-38C) t=6D) t=9/4

At time t, there are 216t + 18 bacteria of type A and 362t + 8 bacteria of type B organisms in a sample. When will the number of each type of bacteria be equal?

Answers voices are:

A) t=38

B) t=-38

C) t=6

D) t=9/4