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1 January, 16:03

If m^2 + n^2 = 18 and mn=7, what is (m-n) ^2

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Answers (2)
  1. 1 January, 17:44
    0
    (m - n) ^2 = 4

    Step-by-step explanation:

    (m - n) ^2 = m^2 - 2mn + n^2 when (m-n) ^2 is expanded using foil.

    But m^2 + n^2 = 18 Given

    mn = 7 Given

    (m - n) ^2 = m^2 + n^2 - 2 mn Substitute in the given values

    (m - n) ^2 = 18 - 2*7 Reduce

    (m - n) ^2 = 18 - 14 Combine

    (m - n) ^2 = 4
  2. 1 January, 18:06
    0
    (m-n) ^2 = m^2 - 2mn + n^2

    (m-n) ^2 = m^2 + n^2 - 2mn

    Substitute m^2 + n^2 = 18 and mn=7

    (m-n) ^2 = 18 - 2 (7)

    (m-n) ^2 = 18 - 14

    (m-n) ^2 = 4
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