Write an equation of an ellipse in standard form with the center at the origin and a height of 12 units and width of 19 units.

The equation of the ellipse in standard form is 4x²/361 + y²/36 = 1

Step-by-step explanation:

* Lets revise the equation of the ellipse

- The standard form of the equation of an ellipse with center (0, 0)

and major axis parallel to the x-axis is x²/a² + y²/b² = 1

# a > b

- The length of the major axis is 2a

- The coordinates of the vertices are (± a, 0)

- The length of the minor axis is 2b

- The coordinates of the co-vertices are (0, ± b)

- The coordinates of the foci are (± c, 0), where c ² = a ² - b²

* Lets solve the problem

∵ The center of the ellipse is (0,0)

∵ Its width is 19 units

∴ The length of the major axis is = 19

∴ 2a = 19 ⇒ divide both sides by 2

∴ a = 19/2 ⇒ ∴ a² = 361/4

∵ Its height is 12 units

∴ The length of the minor axis is = 12

∴ 2b = 12 ⇒ divide both sides by 2

∴ b = 12/2 = 6 ⇒ ∴ b² = 36

- Lets write the equation in standard form

∵ The equation is x²/a² + y²/b² = 1

∴ x² / (361/4) + y²/36 = 1 ⇒ simplify it

∴ 4x²/361 + y²/36 = 1

* The equation of the ellipse in standard form is 4x²/361 + y²/36 = 1