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20 August, 12:31

What is the solution to the equation StartFraction negative 3 d Over d squared minus 2 d minus 8 EndFraction + StartFraction 3 Over d minus 4 EndFraction = StartFraction negative 2 Over d + 2 EndFraction? d = - 4 and d = 2 d = - 2 and d = 4 d = 1 d = 2

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Answers (2)
  1. 20 August, 13:09
    0
    d = 1

    Step-by-step explanation:

    -3d / (d²-2d-8) + 3 / (d-4) = - 2 / (d+2)

    d²-2d-8 = d²-4d+2d-8

    = d (d-4) + 2 (d-4)

    = (d+2) (d-4)

    Since these the factors in the denominator, they can't be zero.

    d cannot be 4 or - 2

    -3d/[ (d+2) (d-4) ] + 3 / (d-4) = - 2 / (d+2)

    Multiply both sides by: (d+2) (d-4)

    -3d + 3 (d+2) = - 2 (d-4)

    -3d + 3d + 6 = - 2d + 8

    2d = 2

    d = 1
  2. 20 August, 16:25
    0
    C on Edge2020 (d = 1)
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