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27 January, 13:12

The length of a rectangle is 4 feet longer than twice the width of the same rectangle. if the perimiter of the rectangle is 68 feet, what are the dimensions of this rectangle?

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  1. 27 January, 16:05
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    Length (L) : 2w + 4

    width (w) : w

    Perimeter (P) = 2L + 2w

    68 = 2 (2w + 4) + 2 (w)

    68 = 4w + 8 + 2w

    68 = 6w + 8

    60 = 6w

    10 = w

    Length (L) : 2w + 4 = 2 (10) + 4 = 20 + 4 = 24

    Answer: width = 10 feet, length = 24 feet
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