What is the 45th team of the arithmetic sequence 58,61,64,67

The 45th term is 190.

Step-by-step explanation:

The easiest way to approach this problem is to find an equation for the nth term of the sequence. Here the first term is 58 and the common difference is 3; that is, each term is equal to the previous term, plus 3. The appropriate equation is thus:

a (n) = a (1) + 3 (n-1). Check. What is a (2) ? Find 58 + 3 (1). It's 61, and correct.

Therefore, the 45th term is:

a (45) = 58 + 3 (45-1) = 58 + 3 (44) = 190