Ask Question
20 July, 09:10

The area of a playground is 216 yd^2. The width of the playground is 6 yd longer than its length. Find the length and width of the playground, including appropriate u its. Show work

+4
Answers (1)
  1. 20 July, 12:29
    0
    Let the length of the playground be x, then the width is 6 + x.

    Area = length * width = x * (6 + x) = 6x + x^2 = 216

    Solving the quadratic equation x^2 + 6x - 216 = 0, we have x = 12 or - 18

    i. e length = 12 and width = 6 + 18 = 18
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “The area of a playground is 216 yd^2. The width of the playground is 6 yd longer than its length. Find the length and width of the ...” in 📘 Mathematics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers