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8 July, 15:03

a ball is dropped from a height of 784ft. It's height h, in feet, after t seconds is given by h (t) = 784-16tsquared. After how long will the ball reach the ground?

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  1. 8 July, 15:51
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    h (t) = - 16t2 + 64

    Time to reach ground:

    h (t) = 0

    -16t2 + 64 = 0

    Solve for t, keeping only the positive solution.

    Time to fall 36 ft:

    Since it is dropped from 64 ft, its height after falling 36 feet is 64-36=28 ft.

    28 = - 16t2 + 64

    -16t2 + 36 = 0
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