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24 November, 08:18

An experiment consists of rolling a die, flipping a coin, and spinning a spinner divided into 4 equal regions. The number of elements in the sample space of this experiment is

12

3

6

48

+4
Answers (2)
  1. 24 November, 10:59
    0
    48

    Step-by-step explanation:

    In the given experiment, three events take place which include rolling a die, flipping a coin and spinning a spinner.

    The possible outcomes of each of these events are as follows:

    Rolling a die - 6

    Flipping a coin - 2

    Spinning a spinner - 4

    Therefore, by multiplying their possible outcomes, we can find the number of elements in the sample space of this environment.

    Number of elements = 6 * 2 * 4 = 48
  2. 24 November, 11:02
    0
    48

    Step-by-step explanation:

    The sample space of the experiment contains all the possible outcomes of all events.

    There are 3 events that are taking place.

    Rolling a die which has 6 possible outcomes.

    Flipping a coin which has 2 possible outcomes.

    Spinning a spinner which has 4 possible outcomes.

    Since the outcome of each event is independent of the other, the total possible outcomes will be equal to the product of outcomes of each event.

    i. e.

    Total outcomes = 6 x 2 x 4 = 48

    The sample space of the experiment contains all the possible outcomes. so the number of elements in the sample space of this experiment will be 48
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