Using the equation-x^2-8x-15 what are the coordinates of the vertex

(-4, 1)

Step-by-step explanation:

Start with - x^2-8x-15. Rewrite it as y = - 1 (x^2 + 8x + 15).

Focus on the terms x^2 + 8x; complete the square here:

x^2 + 8x + 16 - 16, or (x + 4) ^2 - 16.

Put this back into y = - 1 (x^2 + 8x + 15) as follows:

y = - ((x + 4) ^2 - 16 + 15)

Simplify this result: y = - (x + 4) ^2 + 1

Compare this result to y = a (x-h) ^2 + k. See that h = - 4 and k = 1.

The coordinates of the vertex are (-4, 1).