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12 December, 04:43

Find the maximum and minimum values of the function

f (x) = x^3-3x, x∈{-2,2}

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  1. 12 December, 08:03
    0
    x^3 - 3x = 0

    Take the derivative

    f' (x) = 3x^2 - 3 = 0

    Solving by quadratic formula

    Maximum at x = - 1 and

    Minimum at x = + 1
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